If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is:
If a person X wants to distribute pens among 6 children such that A gets twice of B, three times of C, four of D, five of E, and six of F, what is the minimum number of pens needed for each to get an even number?